AC9M9SP01Year 9SpacePractised on site

AC9M9SP01 — Year 9 Space

Official Curriculum Content Description:

recognise the constancy of the sine, cosine and tangent ratios for a given angle in right-angled triangles using properties of similarity

Worked Examples (2)

Example 1Trigonometric Ratios (Sine, Cosine, Tangent)
In a right-angled triangle, angle A=20∘A = 20^\circ and the hypotenuse is 14 cm14\text{ cm}. Find the length of the side adjacent to angle AA, xx. Give your answer to 1 decimal place.
ABC14 cmx20°
Diagram not accurately drawn
Common mistake: Fixing opposite/adjacent to the triangle orientation rather than angle AA, erroneously using sin⁡(20∘)\sin(20^\circ) instead of cos⁡(20∘)\cos(20^\circ).
Correct Answer:13.2 cm13.2\text{ cm}
Accepted: A unit is optional (cm accepted).
Worked Solution:
1. Identify the ratio: cos⁡A=adjacenthypotenuse\cos A = \frac{\text{adjacent}}{\text{hypotenuse}}. 2. Rearrange for the adjacent side: x=hypotenuse×cos⁡A=14×cos⁡(20∘)x = \text{hypotenuse} \times \cos A = 14 \times \cos(20^\circ). 3. x≈13.2 cmx \approx 13.2\text{ cm}.
Example 2Inverse Trigonometric Functions
In a right-angled triangle, the side adjacent to angle xx is 5 cm5\text{ cm} and the hypotenuse is 9 cm9\text{ cm}. Find the angle xx in degrees. Give your answer to 1 decimal place.
ABC9 cm5 cmx
Diagram not accurately drawn
Common mistake: Forgetting to apply the inverse function cos⁡−1\cos^{-1} when finding an angle from a ratio, leaving the side ratio as the answer.
Correct Answer:56.356.3
Worked Solution:
1. Use the inverse cosine function: cos⁡x=adjacenthypotenuse=59\cos x = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{5}{9}. 2. x=cos⁡−1(59)=cos⁡−1(0.5556)x = \cos^{-1}\left(\frac{5}{9}\right) = \cos^{-1}(0.5556). 3. x≈56.3∘x \approx 56.3^\circ.

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