AC9M9M03Year 9MeasurementPractised on site

AC9M9M03 — Year 9 Measurement

Official Curriculum Content Description:

solve spatial problems, applying angle properties, scale, similarity, Pythagoras’ theorem and trigonometry in right-angled triangles

Worked Examples (2)

Example 1Area & Volume Ratios under Scaling
Solid A has a volume of 30 m330\text{ m}^3. Solid A is enlarged by a length scale factor of k=5k = 5 to form Solid B. Calculate the volume of Solid B.
Common mistake: Applying the length scale factor kk directly to volume instead of k3k^3.
Correct Answer:3750 m33750\text{ m}^3
Accepted: A unit is optional (m^3, m³, cu m all accepted).
Worked Solution:
1. Volume scale factor = k3=53=125k^3 = 5^3 = 125. 2. Volume of Solid B = 30×125=3750 m330 \times 125 = 3750\text{ m}^3.
Example 2Angles of Elevation & Depression
An observer stands 75 m75\text{ m} away from the base of a vertical tower. The angle of elevation to the top of the tower is 55∘55^\circ. Calculate the height of the tower hh. Give your answer to 1 decimal place.
TopObserverBase75 mh55°
Diagram not accurately drawn
Common mistake: Measuring the angle of elevation from the vertical tower line instead of the horizontal ground line.
Correct Answer:107.1 m107.1\text{ m}
Accepted: A unit is optional (m accepted).
Worked Solution:
1. The ground distance, tower height, and line of sight form a right-angled triangle. 2. tan⁡(55∘)=heightdistance=h75\tan(55^\circ) = \frac{\text{height}}{\text{distance}} = \frac{h}{75}. 3. h=75×tan⁡(55∘)≈107.1 mh = 75 \times \tan(55^\circ) \approx 107.1\text{ m}.

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