AC9M8P01Year 8ProbabilityPractised on site

AC9M8P01 — Year 8 Probability

Official Curriculum Content Description:

recognise that complementary events have a combined probability of one; use this relationship to calculate probabilities in applied contexts

Worked Examples (1)

Example 1Complement Rule (P(not A) = 1 - P(A))
The probability of event AA occurring is P(A)=710P(A) = \frac{7}{10}. Find the probability of its complement, P(A′)P(A'), which is the probability of event AA not occurring. Express your answer as a fraction in its lowest terms.
Common mistake: Returning the probability of the event itself (P(A)=710P(A) = \frac{7}{10}) instead of subtracting it from 11.
Correct Answer:3/103/10
Worked Solution:
Using the complement rule P(A′)=1−P(A)P(A') = 1 - P(A): 1−710=10−710=3101 - \frac{7}{10} = \frac{10 - 7}{10} = \frac{3}{10}.

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